Given: GS = 435 kt.Distance from A to B = 1920 NM. What is the time from A to B?4
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Given: GS = 480 kt.Distance from A to B = 5360 NM. What is the time from A to B?4
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Given:M 0.80, OAT -50°C, FL 330,GS 490 kt, VAR 20°W,Magnetic heading 140°, Drift is 11° Right.Calculate the true W/V?4
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Given:TAS = 370 KT True HDG = 181°W/V = 095°(T) / 35 KTCalculate the true track and GS?4
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Given:TAS = 170 kt, HDG(T) = 100°,W/V = 350/30kt.Calculate the Track (°T) and GS?4
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Given:TAS = 250 kt, HDG (T) = 029°,W/V = 035/45kt. Calculate the drift and GS?4
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Given:TAS = 270 kt, Track (T) = 260°,W/V = 275/30kt.Calculate the HDG (°T) and GS?4
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Given:True HDG = 145°, TAS = 240 kt, Track (T) = 150°, GS = 210 kt.Calculate the W/V?4
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Given:Maximum allowable tailwind component for landing 10 kt. Planned runway 05 (047° magnetic).The direction of the surface wind reported by ATIS 210°. Variation is 17°E.Calculate the maximum allowable wind speed that can be accepted without exceeding the tailwind limit?4
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Given:Runway direction 230°(T), Surface W/V 280°(T)/40 kt.Calculate the effective cross-wind component?4
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