ATPL - Airline Transport Pilot license - General Navigation Page 14

Questions General Navigation - ATPL Page 14

Given: GS = 435 kt.Distance from A to B = 1920 NM. What is the time from A to B?	4 Answers
Given: GS = 480 kt.Distance from A to B = 5360 NM. What is the time from A to B?	4 Answers
Given:M 0.80, OAT -50°C, FL 330,GS 490 kt, VAR 20°W,Magnetic heading 140°, Drift is 11° Right.Calculate the true W/V?	4 Answers
Given:TAS = 370 KT True HDG = 181°W/V = 095°(T) / 35 KTCalculate the true track and GS?	4 Answers
Given:TAS = 170 kt, HDG(T) = 100°,W/V = 350/30kt.Calculate the Track (°T) and GS?	4 Answers
Given:TAS = 250 kt, HDG (T) = 029°,W/V = 035/45kt. Calculate the drift and GS?	4 Answers
Given:TAS = 270 kt, Track (T) = 260°,W/V = 275/30kt.Calculate the HDG (°T) and GS?	4 Answers
Given:True HDG = 145°, TAS = 240 kt, Track (T) = 150°, GS = 210 kt.Calculate the W/V?	4 Answers
Given:Maximum allowable tailwind component for landing 10 kt. Planned runway 05 (047° magnetic).The direction of the surface wind reported by ATIS 210°. Variation is 17°E.Calculate the maximum allowable wind speed that can be accepted without exceeding the tailwind limit?	4 Answers
Given:Runway direction 230°(T), Surface W/V 280°(T)/40 kt.Calculate the effective cross-wind component?	4 Answers

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