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Id 507 - ATPL - Two points A and B are 1000 NM apart. TAS = 490 kt.On the flight between A and B the equivalent wind is -20 kt.On the return leg between B and A, the equivalent wind is +40 kt.What distance from A, along the route A to B, is the Point of Equal Time (PET)?
Question id 507 - General Navigation - ATPL - Airline Transport Pilot license
Explanation: Two points A and B are 1000 NM apart. TAS = 490 kt.On the flight between A and B the equivalent wind is -20 kt.On the return leg between B and A, the equivalent wind is +40 kt.What distance from A, along the route A to B, is the Point of Equal Time (PET)?
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