General Navigation - ATPL - Airline Transport Pilot license

Question 1

Given:TAS = 270 kt, True HDG = 145°,Actual wind = 205°(T)/30kt. Calculate the drift angle and GS?

Accepted Answer

Curve convex to the equator

Answer

Complex curve

Answer

Curve concave to the equator

Answer

Straight line

Question 2

Waypoints can be entered in an INS memory in different formats.In which of the following formats can waypoints be entered into all INSs?

Accepted Answer

1347 UTC

Answer

1401 UTC

Answer

1333 UTC

Answer

After flying 70 NM along track from 'A', the aircraft is 3 MIN ahead of planned time.Using the actual GS experienced, what is the revised ETA at 'B'? 1401 UTC 1333 UTC 1340 UTC

Question 3

What is the average track (M) and distance between WTD NDB (N5211.3 W00705.0) and KER NDB (N5210.9 W00931. 5)?

Accepted Answer

Parallel of origin

Answer

North and south limits of the chart

Answer

Standard parallels

Answer

Equator

Question 4

Which one of the following, concerning great circles on a Direct Mercator chart, is correct?

Accepted Answer

With the exception of meridians and the equator, they are curves concave to the equator

Answer

They approximate to straight lines between the standard parallels

Answer

They are all curves concave to the equator

Answer

They are all curves convex to the equator

Question 5

The duration of civil twilight is the time:

Accepted Answer

Between sunset and when the centre of the Sun is 6° below the true horizon

Answer

Needed by the Sun to move from the apparent height of 0° to the apparent height of 6°

Answer

Agreed by the international aeronautical authorities which is 12 minutes

Answer

Between sunset and when the centre of the Sun is 12° below the true horizon

Question 6

For a distance of 1860 NM between Q and R, a ground speed 'out' of 385 kt, a ground speed 'back' of 465 kt and an endurance of 8 HR (excluding reserves) the distance from Q to the point of safe return (PSR) is:

Accepted Answer

38.1

Answer

20.6

Answer

54.2

Answer

44.5

Question 7

Given:Maximum allowable tailwind component for landing 10 kt. Planned runway 05 (047° magnetic).The direction of the surface wind reported by ATIS 210°. Variation is 17°E.Calculate the maximum allowable wind speed that can be accepted without exceeding the tailwind limit?

Accepted Answer

11 kt

Answer

18 kt

Answer

15 kt

Answer

8 kt

Question 8

At what approximate date is the Earth furthest from the Sun (aphelion)?

Accepted Answer

Beginning of July

Answer

End of September

Answer

Beginning of January

Answer

End of December

Question 9

A great circle track joins position A (59°S 141°W) and B (61°S 148°W). What is the difference between the great circle track at A and B?

Accepted Answer

It increases by 6°

Answer

It increases by 3°

Answer

It decreases by 6°

Answer

It decreases by 3°

Question 10

Given:TAS = 155 kt, HDG (T) = 216°,W/V = 090/60kt.Calculate the Track (°T) and GS.

Accepted Answer

231 - 196 kt

Answer

224 - 175 kt

Answer

226 - 186 kt

Answer

222 - 181 kt

Quiz General Navigation - ATPL - Airline Transport Pilot license

Test 10 Questions ATPL - Airline Transport Pilot license - General Navigation, no time limit