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Questions Navigation - Private Pilot (Helicopter)

An aircraft is following a true course (TC) of 040° at a constant true airspeed (TAS) of 180 kt. The wind vector is 350°/30 kt. The groundspeed (GS) equals... 4 Answers An aircraft is following a true course (TC) of 040° at a constant true airspeed (TAS) of 180 kt. The wind vector is 350°/30 kt. What is the wind correction angle (WCA), including sign? 4 Answers Given: True course: 270°. TAS: 100 kt. Wind: 090°/25 kt. Distance: 100 NM. The ground speed (GS) equals... 4 Answers Given: True course: 270°. TAS: 100 kt. Wind: 090°/25 kt. Distance: 100 NM. The flight time equals... 4 Answers An aircraft is following a true course (TC) of 040° at a constant true airspeed (TAS) of 180 kt. The wind vector is 350°/30 kt. In which direction is the wind correction angle (WCA)? 4 Answers Given: True course: 120°. TAS: 120 kt. Wind: 150°/12 kt. The WCA equals... 4 Answers The distance from 'A' to 'B' measures 120 NM. At a distance of 55 NM from 'A' the pilot realizes a deviation of 7 NM to the right. What approximate course change must be made to reach 'B' directly? 4 Answers An aircraft has a heading of 090°. The distance to be flown is 90 NM. After 45 NM the aircraft is 4.5 NM north of the planned flight path. What corrected heading should be flown to reach the destination aerodrome directly? 4 Answers What is the meaning of the 1:60 rule? 4 Answers An aircraft is flying from 'A' to 'B' (distance 220 NM) at an average ground speed (GS) of 120 kt. It departs 'A' at 1200 UTC. After 70 NM along the course from 'A', the aircraft is 5 min ahead of the planned schedule. Using the actual GS, what is the revised estimated time of arrival (ETA) at B? 4 Answers

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