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Given:True course A to B = 250° Distance A to B = 315 NM TA
Given:True course A to B = 250° Distance A to B = 315 NM TAS = 450 kt.W/V = 200°/60kt. ETD A = 0650 UTC.What is the ETA at B?
Domanda 302, General Navigation - ATPL - Airline Transport Pilot license
0730 UTC
0736 UTC
What is the ETA at B? 0730 UTC 0736 UTC 0716 UTC
0810 UTC
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