Given: GS = 510 kt. Distance A to B = 43 NMWhat is the time (MIN) from A to B?

Question

ATPL - Airline Transport Pilot license - General Navigation - Given: GS = 510 kt. Distance A to B = 43 NMWhat is the time (MIN) from A to B?

QuizVDS · Accepted Answer

Mean scale between the parallels of the secant cone

QuizVDS · Answer

Mean scale between pole and equator

QuizVDS · Answer

Scale at the standard parallels

QuizVDS · Answer

Scale at the equator

ATPL: Given: GS = 510 kt. Distance A to B = 43 NMWhat is the time (MIN) from A to B?