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ATPL - Airline Transport Pilot license - General Navigation

Questions General Navigation - ATPL

Given:TAS = 480 kt, HDG (°T) = 040°,W/V = 090/60kt.Calculate the Track (°T) and GS?4
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Given:TAS = 230 kt, HDG (T) = 250°,W/V = 205/10kt. Calculate the drift and GS?4
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Given:TAS = 465 kt, Track (T) = 007°,W/V = 300/80kt.Calculate the HDG (°T) and GS?4
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Given:True HDG = 054°, TAS = 450 kt, Track (T) = 059°, GS = 416 kt.Calculate the W/V?4
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Given:For take-off an aircraft requires a headwind component of at least 10 kt and has a cross-wind limitation of 35 kt.The angle between the wind direction and the runway is 60°, Calculate the minimum and maximum allowable wind speeds?4
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Given:FL 350,Mach 0.80, OAT -55°C.Calculate the values for TAS and local speed of sound (LSS)?4
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Given:True altitude 9000 FT, OAT -32°C,CAS 200 kt.What is the TAS?4
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An aircraft was over 'A' at 1435 hours flying direct to 'B'. Given:Distance 'A' to 'B' 2900 NM True airspeed 470 ktMean wind component 'out' +55 kt Mean wind component 'back' -75 kt Safe endurance 9 HR 30 MINThe distance from 'A' to the Point of Safe Return (PSR) 'A' is:4
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Given:Distance 'Q' to 'R' 1760 NM Groundspeed 'out' 435 kt Groundspeed 'back' 385 ktThe time from 'Q' to the Point of Equal Time (PET) between 'Q' and 'R' is:4
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A ground feature was observed on a relative bearing of 325° and five minutes later on a relative bearing of 280°. The aircraft heading was 165°(M), variation 25°W, drift 10°Right and GS 360 kt. When the relative bearing was 280°, the distance and true bearing of the aircraft from the feature was:4
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