A course of 120°(T) is drawn between 'X' (61°30'N) and 'Y' (58°30'N) on a Lambert Conformal conic chart with a scale of 1: 1 000 000 at 60°N.The chart distance between 'X' and 'Y' is:4
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What is the average track (M) and distance between WTD NDB (N5211.3 W00705.0) and KER NDB (N5210.9 W00931. 5)?4
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Given:True course from A to B = 090°, TAS = 460 KT,W/V = 360/100 KT,Average variation = 10°E, Deviation = -2°.Calculate the compass heading and GS?4
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Assume a North polar stereographic chart whose grid is aligned with the Greenwich meridian.An aircraft flies from the geographic North pole for a distance of 480 NM along the 110°E meridian, then follows a grid track of 154° for a distance of 300 NM. Its position is now approximately:4
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An aircraft was over 'Q' at 1320 hours flying direct to 'R'. Given:Distance 'Q' to 'R' 3016 NM True airspeed 480 ktMean wind component 'out' -90 kt Mean wind component 'back' +75 ktThe ETA for reaching the Point of Equal Time (PET) between 'Q' and 'R' is:4
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Given:ILS GP angle = 3.5 DEG, GS = 150 KT.What is the approximate rate of descent?4
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Given: GS = 510 kt. Distance A to B = 43 NMWhat is the time (MIN) from A to B?4
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Given: GS = 95 kt.Distance from A to B = 480 NM. What is the time from A to B?4
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What is the ratio between the litre and the US-GAL ?4
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The reported surface wind from the Control Tower is 240°/35 kt. Runway 30 (300°). What is the cross-wind component?4
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