An aircraft was over 'Q' at 1320 hours flying direct to 'R'. Given: Distance 'Q' to 'R' 3016 NM True airspeed 480 kt Mean wind component 'out' -90 kt Mean wind component 'back' +75 kt The ETA for reaching the Point of Equal Time (PET) between 'Q' and 'R' is:4
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Given: ILS GP angle = 3.5 DEG, GS = 150 KT. What is the approximate rate of descent?4
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Given: GS = 510 kt. Distance A to B = 43 NM. What is the time (MIN) from A to B?4
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Given: GS = 95 kt. Distance from A to B = 480 NM. What is the time from A to B?4
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What is the ratio between the litre and the US-GAL?4
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The reported surface wind from the Control Tower is 240°/35 kt. Runway 30 (300°). What is the cross-wind component?4
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Given: TAS = 270 kt, True HDG = 145°, Actual wind = 205°(T)/30kt. Calculate the drift angle and GS?4
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Given: TAS = 132 kt, True HDG = 257°W/V = 095°(T)/35kt. Calculate the drift angle and GS?4
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Given: TAS = 465 kt, HDG (T) = 124°,W/V = 170/80kt. Calculate the drift and GS?4
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Given: TAS = 227 kt, Track (T) = 316°,W/V = 205/15kt. Calculate the HDG (°T) and GS?4
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Other exam subjects ATPL - Airline Transport Pilot license