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With no crosswind, TAS 180 kt and a direct headwind of 25 kt, approximately what distance is covered in 2 h 25 min? 4 Answers Approximately what is TAS for CAS 155 kt, pressure altitude 8000 ft and OAT +15 °C? 4 Answers What is the true course (TC) from Uelzen (EDVU) (52°59'N, 010°28'E) to Neustadt (EDAN) (53°22'N, 011°37'E)? See annex (NAV-031) 4 Answers At pressure altitude 7500 ft, the temperature is −9 °C and QNH-indicated altitude is 6500 ft. For this exercise assume the mean-layer deviation from ISA equals the deviation at flight level, use 4 ft per 1000 ft per °C above a sea-level reference and round to the nearest 250 ft. What is estimated true altitude? 4 Answers What is the distance from Neustadt (EDAN) (53°22'N, 011°37'E) to Uelzen (EDVU) (52°59'N, 010°28'E)? See annex (NAV-031) 4 Answers At pressure altitude 7000 ft, OAT is +11 °C and QNH-indicated altitude is 6500 ft. Assume the mean-layer deviation equals that at flight level; use ISA +15 °C at sea level and a lapse rate of 2 °C per 1000 ft, then 4 ft per 1000 ft per °C temperature correction above a sea-level reference. Round true altitude to the nearest 250 ft. 4 Answers At pressure altitude 7000 ft, OAT is +21 °C and QNH-indicated altitude is 6500 ft. Assume the mean-layer deviation equals that at flight level; use ISA +15 °C at sea level and a lapse rate of 2 °C per 1000 ft, then 4 ft per 1000 ft per °C temperature correction above a sea-level reference. Round true altitude to the nearest 250 ft. 4 Answers Given: True course: 255°. TAS: 100 kt. Wind: 200°/10 kt. The true heading equals... 4 Answers Given: True course: 165°. TAS: 90 kt. Wind: 130°/20 kt. Distance: 153 NM. The true heading equals... 4 Answers Given: Ground speed (GS): 160 kt. True course (TC): 177°. Wind vector (W/WS): 140°/20 kt. The true heading (TH) equals... 4 Answers

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