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Id 1 - ATPL - An aircraft is flying at MACH 0.84 at FL 330. The static air temperature is -48°C and the headwind component 52 Kt. At 1338 UTC the controller requests the pilot to cross the meridian of 030W at 1500 UTC. Given the distance to go is 570 NM, the reduced MACH No. should be:
Question id 1 - Flight Planning and Monitoring - ATPL - Airline Transport Pilot license
0.76
0.78
Given the distance to go is 570 NM, the reduced MACH No. should be: 0.76 0.78 0.72
Explanation: An aircraft is flying at MACH 0.84 at FL 330. The static air temperature is -48°C and the headwind component 52 Kt. At 1338 UTC the controller requests the pilot to cross the meridian of 030W at 1500 UTC. Given the distance to go is 570 NM, the reduced MACH No. should be:
EN 